Once we have direction vector from to, our parametric equations will be This vector quantifies the distance and direction of an imaginary motion along a straight line from the first point to the second point. We need to find components of the direction vector also known as displacement vector.
Let's find out parametric form of a line equation from the two known points and.
#Graph maker linear equation how to#
The line equation, in this case, becomes How to find the slope-intercept equation of a line example Note that in the case of a horizontal line, the slope is zero and the intercept is equal to the y-coordinate of points because the line runs parallel to the x-axis. The line equation, in this case, becomes Equation of a horizontal line Note that in the case of a vertical line, the slope and the intercept are undefined because the line runs parallel to the y-axis. So, once we have a, it is easy to calculate b simply by plugging or to the expression above.įinally, we use the calculated a and b to write the result as įor two known points we have two equations in respect to a and b Let's find slope-intercept form of a line equation from the two known points and. How to find the equation of a line in slope-intercept form
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